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(PHP 3, PHP 4, PHP 5)

mysql_field_name -- Get the name of the specified field in a result

Description

string mysql_field_name ( resource result, int field_offset )

mysql_field_name() returns the name of the specified field index.

Parameters

result

The result resource that is being evaluated. This result comes from a call to mysql_query() .

field_offset

The numerical field offset. The field_offset starts at 0 . If field_offset does not exist, an error of level E_WARNING is also issued.

Return Values

The name of the specified field index on success, or FALSE on failure.

Examples

Example 1. mysql_field_name() example

<?php
/* The users table consists of three fields:
*   user_id
*   username
*   password.
*/
$link = @mysql_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
    die('Could not connect to MySQL server: ' . mysql_error());
}
$dbname = 'mydb';
$db_selected = mysql_select_db($dbname, $link);
if (!$db_selected) {
    die("Could not set $dbname: " . mysql_error());
}
$res = mysql_query('select * from users', $link);

echo mysql_field_name($res, 0) . "\n";
echo mysql_field_name($res, 2);
?>

The above example will output:

user_id
password

Notes

Related Function(s)

mysql_query()